The answer is C because AO and BO are equal. And with AO being three times the length of CO, BO should be the length of DO
Because there nobody that teaches them how to do math
Answer:
25
Step-by-step explanation:
By counting the height ( frequency ) of each block and adding gives the number of students in total
20 - 24 → 5
24 - 28 → 6
28 - 32 → 5
32 - 36 → 2
36 - 40 → 7
Total = 5 + 6 + 5 + 2 + 7 = 25
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
y≥1
Step-by-step explanation:
hello :
y-1≥0
y-1+1≥0+1
y≥1
