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SOVA2 [1]
4 years ago
14

Twelve colored cubes are arranged in a row. There are 3 blue cubes, 2 yellow cubes, 3 red cubes, and 4 green cubes, but not in t

hat order. There is a yellow cube at one end and a red cube at the other end. The red cubes are all touching. The green cubes are also all touching. The tenth cube from the left is blue. What color is the sixth cube from the left
Mathematics
1 answer:
Mashutka [201]4 years ago
3 0

Answer:

The sixth cube from the left is a green cube.

Step-by-step explanation:

There are 12 cubes, 3 blue cubes, 2 yellow cubes, 3 red cubes, and 4 green cubes.

Let B, Y, R and G represent blue, yellow, red and green cubes respectively.

The arrangement will be predicted with the information provided

- There is a yellow cube at one end and a red cube at the other end. There are two models to this.

Y, , , , , , , , , , , R

Or

R, , , , , , , , , , , Y

- The red cubes are all touching. Note that there are 3 red cubes

Y, , , , , , , , , R, R, R

Or

R, R, R, , , , , , , , , Y

- The green cubes are also all touching and the tenth cube from the left is blue.

We first position the blue cube at a position tenth from the left

Y, , , , , , , , , R, R, R

With this configuration, the blue cube will be taking the position of a red cube and that violates the rule that the 3 red ctubes are touching, Hence, it is evident that the 2nd model we're examining is the correct one

We then position the blue cube at a position tenth from the left in the 2nd model

R, R, R, , , , , , , B, , Y

Then all the 4 green cubes are touching, they could be placed in a number of ways

R, R, R, G, G, G, G, , , B, , Y

Or

R, R, R, , G, G, G, G, , B, , Y

Or

R, R, R, , , G, G, G, G, B, , Y

Note that in each of the 3 possible ways this can happen, the sixth cube from the left is always a green cube.

Hence, the sixth cube from the left is a green cube.

Hope this Helps!!!

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Need help!! please/Thank you
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Answer:

50~in

Step-by-step explanation:

perimter=AB+AM+BM

AM=2EM=2(9in)=18in

BM=25E=2(7in)=14in

∠m= 180- (∠A+∠B)= 180-(70+40)

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<u>--------------------------</u>

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5 0
3 years ago
Read 2 more answers
Assembly Department $280,000
DIA [1.3K]
<h2><u>Answer :-</u></h2>

A. Commercial 540

Residential 360

B. Commercial 585

Residential 390

<h2><u>Explanation :-</u></h2>

a) Calculation to Determine the per-unit factory overhead allocated to the commercial and residential motors .

First step is to calculate the Plantwide overhead rate using this formula

Plantwide overhead rate =Estimated overhead /Estimated machine hours

Let plug in the formula

Plantwide overhead rate = 1080000/9000

Plantwide overhead rate = $ 120 per MH

Now let Determine the per-unit factory overhead allocated to the commercial and residential motors

Using this formula

Per -unit factory overhead allocated=Actual MH per unit *Plantwide overhead rate

Let plug in the formula

Per -unit factory overhead allocated to COMMERCIAL=4.5 dmh*120

Per -unit factory overhead allocated to COMMERCIAL=540

Per -unit factory overhead allocated to RESIDENTIAL=3.0 dmh*120

Per -unit factory overhead allocated to RESIDENTIAL=360

Therefore the per-unit factory overhead allocated to the commercial and residential motors under the single plantwide factory overhead rate method will be:

Commercial 540

Residential 360

b. Calculation to Determine the per-unit factory overhead allocated to the commercial and residential motors

First step is to calculate the Departmental overhead rate

ASSEMBLY TESTING

Estimated overhead 280,000 800,000

÷Estimated machine hours each department 4,000 5,000

=Departmental overhead rate 70 160

Now calculation the per-unit factory overhead allocated to the commercial and residential motors

COMMERCIAL RESIDENTIAL

Assembly 1.5 dmh*70=105 1.0 dmh*70=70

Testing 3.0*160= 480 2.0*160= 320

Per -unit factory overhead allocated 585 390

(105+480=585)

(70+320=390)

Therefore the per-unit factory overhead allocated to the commercial and residential motors under the multiple production department factory overhead rate method will be:

Commercial 585

Residential 390

7 0
3 years ago
How do i find all the missing angles, a b c d e I HAVE TO TURN IT IN SOON AA
castortr0y [4]

Step-by-step explanation:

for a

  • a+,38°=90°{ angle at circumference through center is 90°}
  • a=90-38
  • a=52°

for e

  • e=38°{base angle of isosceles triangle r equal}

for d

  • 38°+e+d=180°{sum of angle of triangle}
  • d=180-76
  • d=104°

for. c

  • c+d=180°{straight angle}
  • c=180-104°
  • c=76°

for b

  • a+b+c=180°{sum of angle of triangle}
  • b=180-128
  • b=52°

hope it helps.

<h2>stay safe healthy and happy.</h2>
4 0
3 years ago
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