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SOVA2 [1]
3 years ago
5

Help please?????? I neeeeedc helppp

Mathematics
2 answers:
Sav [38]3 years ago
7 0
Area of rectange = 5 x 8 = 40
area of green triangle = 1/2(8)(1) = 4
area of yellow triangle = 1/2(4)(8) = 16
area of blue triangle = 40 - (4+16) = 40 - 20 = 20

answer
C. 20

V125BC [204]3 years ago
5 0
Yellow=16<span>

green=4

Blue=20</span>
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Erica plotted the three towns closest to her house on a graph with town A
marta [7]
First, determine the distances from the towns.
  Town A to Town B: Opposite angle C
                      d = sqrt ((12 - 7)^2 + (9 - 9)^2)
                      d = 5
  Town B to Town C: Opposite Angle A
                      d = sqrt ((7 - 1)^2 + (9 - 1)^2)
                       d = 10
  Town A to Town C: Opposite Angle B
                       d = sqrt (12 - 1)^2 + (9 - 1)^2)
                        d = 13.6
The angle with largest measure is the one opposite the greatest distance. Thus, the arrangement would be:    C, A, B.
8 0
3 years ago
Which is the graph of y= 2(x-3)^2 +2
WINSTONCH [101]

The graph of y = 2(x - 3)² + 2 can be seen in the attached picture. This problem can be solved through the concept of parabola and transformation.

<h3>Further explanation</h3>

<u>The Problem:</u>

Which is the graph of y = 2(x - 3)² + 2?

<u>Question-1:</u>

How to make a graph y = 2 (x - 3) ² + 2 through the concept of a parabola.

<u>The Process:</u>

The equation of a parabola is given by \boxed{ \ y = a(x - h)^2 + k \ }.

Keep in mind the following points:

  • vertex point at (h, k)
  • axis of symmetry at x = h
  • a > 0 the parabola opens upward
  • a < 0 the parabola opens downward
  • the y-intercept is \boxed{ \ y = ah^2 + k \ } at x = 0.

From our case it can be concluded as follows:

  • the graph of y = 2(x - 3)² + 2 opens upward
  • vertex point at (3, 2)
  • axis of symmetry at x = 3
  • the y-intercept is 2(3²) + 2 = 20 or in coordinates of (0, 20)

<u>Question-2:</u>

How to make the graph of y = 2(x - 3)² + 2 through the transformation.

<u>The Process:</u>

To plot the graph of y = 2(x - 3) ² + 2 we apply for the following transformation order:

Step-1: clearly, to obtain the graph of y = (x - 3)² we shift the graph of y = x² to the right 3 units.

Step-2: to obtain the graph of y = 2(x - 3)², we stretch the graph of y = (x - 3)²  by a factor of 2 (in other words, multiply each y-coordinate by 2).

Step-3: finally, to obtain the graph of y = 2(x - 3)² + 2 we shift the graph of y = 2(x - 3)² upward 3 units.

Thus the construction of the graph y = 2 (x - 3) ² + 2 is completed.

The graph of y = 2(x - 3) ² + 2 is drawn by the combination of shifting the graph of y = x² to the right 3 units and upward 2 units, and also stretch by a factor of 2. Between vertical shift and stretch steps, it is the same whatever steps are taken first.

- - - - - - - - - -

Notes

  • The transformation of graphs is changing the shape and location of a graph.  
  • There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching/shrinking).  
  • In this case, the transformation is shifting horizontally and vertically and also stretching vertically.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:  

\boxed{ \ y = f(x \pm h) \pm v \ }  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right .

Notice the following definitions for stretch and shrink.

  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = cf(x)} by stretching \boxed{ \ c > 1 \ } or shrinking \boxed{ \ 0 < c < 1 \ } the graph of \boxed{y = f(x)} vertically by a factor of c.
  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = f(cx)} by stretching \boxed{ \ 0 < c < 1 \ } or shrinking \boxed{ \ c > 1 \ } the graph of \boxed{y = f(x)} horizontally by a factor of c.
<h3>Learn more  </h3>
  1. What is the y-intercept of the quadratic function  f(x) = (x – 6)(x – 2)? brainly.com/question/1332667
  2. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  3. Which statement correctly describes the graph  brainly.com/question/10929552

8 0
3 years ago
Read 2 more answers
Which statement is true???
HACTEHA [7]

Answer:

The first one; -1.2<6.9

Step-by-step explanation:

7 0
3 years ago
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How can you get 2 1/2÷5/8​
vfiekz [6]

Answer: 4

Step-by-step explanation:

Change the 2.5 to an improper fraction, then multiply by the reciprocal of 5/8.

2\frac{1}{2} /\frac{5}{8} =\frac{5}{2}*\frac{8}{5}=\frac{40}{10}   =4

5 0
3 years ago
Read 2 more answers
A special Olympic event has 16 more boys than girls competing. The total number of participants is 1000. How many boys completed
Ray Of Light [21]

x= the number of girls competing

x+16=the number of boys competing

The equation to find the number of boys and girls competing would be:

x+(x+16)=1000

First, combine like terms:

2x+16=1000

Subtract 16 from both sides.

2x=984

Divide both sides by 2:

x=492

We know now that the number of girls competing is 492. To find the number of boys competing, you simply have to add 16 to 492.

492+16=508

There are 508 boys competing and 492 girls competing.

I hope this helps :)

6 0
3 years ago
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