Question

Please help and thank you!

Answer 1

Since polar coordinates are made up in this way

$(r, \theta )$

we need to solve for r and then find the angle. In our rectangular coordinate given,

$(-4,-4\sqrt{3})$

$x = -4$ and $y=-4\sqrt{3}$

We will use this fact to first find the angle then r, which might seem backwards but I am going to do it in this order. The formula to find the angle measure uses the tangent identity

$tan\theta=\frac{y}{x}$.

Filling in our y and x from the rectangular coordinate we have

$tan\theta=\frac{-4\sqrt{3}}{-4}$ or

$tan\theta =\frac{\sqrt{3}}{1}$.

The tangent identity is the side opposite the reference angle (theta) over the side adjacent to it. Since in our rectangular coordinate both x and y are negative, we will be in QIII where x and y are negative. The side across from the reference angle is the square root of 3, which should tell us at this point in our math careers that the reference angle is a 60 degree angle. But in the third quadrant, the angle is 180+60 which is 240 degrees. Converting that to radians we get $\frac{4\pi}{3}$. That's our angle. In order to solve for r now, we will need the cosine of that angle. In our 30-60-90 right triangle we can solve for the length of the missing side which is the hypotenuse. If our Pythagorean triple is

$(x, x\sqrt{3},2x)$

and x = -4, then the length of the hypotenuse is 2(-4) which is -8 but since a hypotenuse is never negative, it's just 8. That's also the value for r! That means that the polar coordinates that are the same as the rectangular ones we were given are

$(8,\frac{4\pi}{3})$

first choice above.