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olya-2409 [2.1K]
3 years ago
5

ABCD ~ EFGH

Mathematics
1 answer:
vredina [299]3 years ago
4 0

Answer:

FG = 20 in

Step-by-step explanation:

∵ ABCD ≈ EFGH

∴ AD/EH = BC/FG

∵ AD = 45 in

∵ EH = 60 in

∴ BC = 15 in

∴ 45/60 = 15/FG

∴ FG = (60 × 15) ÷ 45 = 20 in

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Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

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3 years ago
I need to know the answer ASAP thank you
ElenaW [278]

Answer:

Step-by-step explanation:

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What is 8/10 subtract 5/10
anzhelika [568]
Since the denominators are the same, just subtract the numerators.
The answer is 3/10.
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Gcf using prime factorization of 52 and 65
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<span>25: 2 × 2 × 13 65: 5 × 13</span>
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Each student needs 35 craft sricks for an art project. The art teacher has 7,140 craft sticks. How many students can get craft s
Karo-lina-s [1.5K]

Answer:

204 students

just do 7140/35= 204

Step-by-step explanation:


6 0
3 years ago
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