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Sever21 [200]
3 years ago
5

Solve log2X=log12X by graphing

Mathematics
2 answers:
Annette [7]3 years ago
8 0

Answer:

B and C

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
5 0

Answer: y1= logx/log2 and y2=logx/log12 (B and C)

Step-by-step explanation:

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Evaluate 5(14 – 23) + 8 ÷ 2.
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Answer:

5of-9+4

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In the diagram AB Is the perpendicular bisector of PH. Help
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Step-by-step explanation:

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3 years ago
Geometry quick question help
vova2212 [387]

Answer:

Angle 1: 127

Angle 2: 153

Step-by-step explanation:

First, let's find angle 1 by finding the angle that's supplementary to it.

To solve for it, we can set up an equation where the unknown angle and the other angles in the triangle it's in add up to 180:

x+95+32=180

x=53

Since angle 1 is supplementary to 53, that means that angle 1 is equal to 180-53 = 127.

Then, to find angle 2, we can find the angle that's supplementary to it.

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3 0
3 years ago
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Points P and Q belong to AB. If AB = a and AP = 2PQ = 2QB, find the distance between: the midpoints of AP and QB.
SCORPION-xisa [38]

Answer:

The distance between midpoint of AP and QB is \frac{5a}{8}.

Step-by-step explanation:

Given that: AB = a

                  AP = 2PQ = 2QB

Thus,

PQ = QB = \frac{a}{4}

PQ + QB = \frac{a}{4}+ \frac{a}{4}

              = \frac{a}{2}

AP = \frac{1}{2} a = \frac{a}{2}

The distance between midpoint of AP and QB can be determined as;

\frac{AP}{2} + PQ + \frac{QB}{2}

= \frac{a}{4} + \frac{a}{4} + \frac{a}{8}

= \frac{2a+2a+a}{8}

 = \frac{5a}{8}

Therefore, the distance between midpoint of AP and QB is \frac{5a}{8}.

5 0
3 years ago
How do you simplify 12(a-4
Romashka [77]
I hope this helps you 12(a-4)=12a-12.4=12a-48
6 0
3 years ago
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