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2 years ago

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8x – 20 is the correct simplified expression for 4(2x – 5). Explain how to verify the simplified expression

2 answers:

MatroZZZ [7]2 years ago

7 0

Not sure if this is right but I would just expand it out again to get 8x-20. ?

aleksandrvk [35]2 years ago

6 0

Using the distributive property, we can go 4(2x) - 4(5) which would equal 8x-20.
Hope this helps and please give brainliest!

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Please help ASAP!!!!!!!

VLD [36.1K]

Answer:

10th term is 10

Step-by-step explanation:

The nth term for finding the geometric progression is expressed as;

Tn = ar^n-1

a is the first term

r is the common ratio

n is the number of terms

a11 = ar^11-1

a11 = ar^10

Since a11 = -5 and r = -1/2

-5 = a(-1/2)^10

-5 = a(1/1024)

a= 1024 * -5

a = -5120

Nest is to get the 10th terms

a10 = ar^9

a10 = -5120 * (-1/2)^9

a10 = -5120 * -1/512

a10 = 10

Hence the 10th term of the sequence is 10

3 0

2 years ago

identify the type of conic section that has the equation 4x^2+25y^2=100 and identify its domain and range.

Vika [28.1K]

4x^2+25y^2=100

$4x^2+25y^2=100 \\\\
Dividing \;both \;sides \;by \;100 \\\\
\frac{4x^2}{100}+ \frac{25y^2}{100}= \frac{100}{100} \\\\
\frac{x^2}{25}+ \frac{y^2}{4}= 1 \\\\
\frac{x^2}{5^2}+ \frac{y^2}{2^2}= 1 \\\\
This \;is \;an \;ellipse. \\\\ \frac{x^2}{a^2}+ \frac{y^2}{b^2}= 1$

Domain of an ellipse is x ∈ [-a,a] and Range of an ellipse is y ∈ [-b,b].

So, given equation is an Ellipse where Domain is x ∈ [-5,5] and Range is y ∈ [-2,2].

4 0

2 years ago

Example of the sistributive property 3x6

Margarita [4]

An example for the distributive property would be 3(1x6)

4 0

2 years ago

Which of the following graphs is the solution set of -10 < 3x - 4 < 8?

sveticcg [70]

Answer:

The First Graph -2○ and 4○

Step-by-step explanation:

Because these numbers aren't included in the solution.

8 0

2 years ago

A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate

sdas [7]

Answer:

442 miles

Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

$x^2 + 1^2 = y^2$

Differentiate w.r.t time (t)

$2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}$

$2x\frac{dx}{dt} = 2y\frac{dy}{dt}$

Divide both sides by 2

$x\frac{dx}{dt} = y\frac{dy}{dt}$

From the question, we have that the plan travels are 510mi/h.

This implies that:

$\frac{dx}{dt} = 510mi/h$

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

$y = 2mi$

Apply Pythagoras theorem

$x^2 + 1^2 = y^2$

$x^2 + 1^2 = 2^2$

$x^2 + 1 = 4$

$x^2 = 4-1$

$x^2 = 3$

$x = \sqrt 3$

So, the expression becomes:

$x\frac{dx}{dt} = y\frac{dy}{dt}$

$\sqrt 3 * 510 = 2* \frac{dy}{dt}$

$\frac{\sqrt 3 * 510}{2} = \frac{dy}{dt}$

$\sqrt 3 * 255 = \frac{dy}{dt}$

$\frac{dy}{dt} = 255\sqrt 3$

$\frac{dy}{dt} = 255 * 1.7321$

$\frac{dy}{dt} = 441.655$

$\frac{dy}{dt} = 442$

<em>Hence, the distance is 442 miles</em>

7 0

2 years ago