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Grace [21]
3 years ago
13

8x – 20 is the correct simplified expression for 4(2x – 5). Explain how to verify the simplified expression

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0
Not sure if this is right but I would just expand it out again to get 8x-20. ?
aleksandrvk [35]3 years ago
6 0
Using the distributive property, we can go 4(2x) - 4(5) which would equal 8x-20.
Hope this helps and please give brainliest!
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A random sample of 20 items is selected from a population. When computing a confidence interval for the population mean, what nu
kumpel [21]

Answer:

For this case since the sample size is lower than 30 , n =20<30, is not appropiate use the normal standard distribution to calculate the confidence interval for the mean, and then for this case is better use the t distribution since takes in count the correction factor to approximate the distribution of the true parameter.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

For this case since the sample size is lower than 30 , n =20<30, is not appropiate use the normal standard distribution to calculate the confidence interval for the mean, and then for this case is better use the t distribution since takes in count the correction factor to approximate the distribution of the true parameter.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

8 0
3 years ago
The mean caloric intake of an adult male is 2800 with a standard deviation of 115. To verify this information, a sample of 25 me
erma4kov [3.2K]

Answer:

Step-by-step explanation:

We would use the t- distribution.

From the information given,

Mean, μ = 2950

Standard deviation, σ = 115

number of sample, n = 25

Degree of freedom, (df) = 25 - 1 = 24

Alpha level,α = (1 - confidence level)/2

α = (1 - 0.98)/2 = 0.01

We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01

The corresponding z score is 2.492

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

2950 ± 2.492 × 115/√25

= 2950 ± 2.492 × 23

= 2950 ± 57.316

The lower end of the confidence interval is 2950 - 57.316 =2892.68

The upper end of the confidence interval is 2950 + 57.316 = 3007.32

The solution is correct.

8 0
3 years ago
Solve each equation. Check your solution.<br> 4t - 2 = 14
anyanavicka [17]
T = 4. first, you can add 2 to both sides of the equation. you get 4t = 16. then, you can divide both sides by 4 to isolate t.
3 0
2 years ago
Read 2 more answers
HELP PLS HELP PLS
ivanzaharov [21]

Answer:

x =-4

y=-1

x=2

y=8

okeeeeeeeeeeeyyyyyyyyy

5 0
2 years ago
Solve for g. Show your work! g+6-3=31
Zielflug [23.3K]

Answer:

g=28, that may not be how the teacher would want you to show your work, but that's how I find the answer!

Step-by-step explanation:

6-3=3

31-3=28

28=g

So therefore 28+6-3=31

6 0
3 years ago
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