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likoan [24]
3 years ago
9

Rewrite the function by completing the square f(x)=x ^2 +4x−60

Mathematics
1 answer:
zhuklara [117]3 years ago
5 0

Hi there! :)

\large\boxed{f(x) = (x + 2)^{2}  - 64}

f(x) = x² + 4x - 60

Rewrite:

0 = x² + 4x - 60

Complete the square by creating a perfect square trinomial. Make sure to add the third term to both sides:

0 + 4 = (x² + 4x + 4) - 60

Rewrite the trinomial as a square binomial:

4 = (x + 2)² - 60

Subtract 4 from both sides:

0 = (x +2)² - 64

Rewrite:

f(x) = (x + 2)² - 64

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Evaluate 4(2a – b) when a = –1 and b = 5.
grin007 [14]

Hey There!

<h2><u>Question:-</u></h2>

\sf \longmapsto \: 4(2a - b)

<em>This is a algebraic expression. The values of a and b are given. The values are as follows :-</em>

a = -1

And,

b = +5 .

<h2><u>Solution</u><u>:</u><u>-</u></h2>

\sf \longmapsto4(2a  -  b)

<em>Note that </em><u>a </u><em>is multiplied with 2 that is :-</em>

\sf \longmapsto4(2 \times a \:  - b)

<u>Now, Insert the values that is a = -1 and b = 5 :-</u>

\sf \longmapsto4(2   \times  -  1 - 5)

Here,we need to follow BODMAS Rule.

B = Brackets

O = Orders

D = Division

M = Multiplication

A = Addition

S = Subtraction

<em>We need to solve the bracket's </em><em>calculations</em><em> </em><em>first</em><em> </em><em>as </em><em>it </em><em>is </em><em>the</em><em> </em><em>rule.</em>

<u>So, Firstly Multiply (2 × -1)</u><u> </u><u>:</u><u>-</u>

\sf \longmapsto4( - 2 - 5)

Note that, (-) × (-) equals to (+).

So, it will be 5+2,But as 5 is bigger number than 2, 5 contains a minus sign.So the result will be -7.

\sf \longmapsto4(  5+ 2)

<em>On Simplification:-</em>

\sf \longmapsto4( - 7)

\sf \longmapsto4  \times (- 7)

\sf \longmapsto \:  - 28

______________________________________

<em>Henceforth the solution of the algebraic expression is :-</em>

\bf \:- 28

Option B is correct!

______________________________________

I hope this helps!

Please let me know if you have any questions.

~MisterBrian

3 0
2 years ago
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FromTheMoon [43]

Answer:

the answer is  3

Step-by-step explanation:

(-5x-3)(-5x+3)=(5x)^2 - (3)^2

A difference of squares is the difference of two squared terms.

We have

a^2 - b^2

We can factorize the difference of squared terms like this:

a^2-b^2 = (a+b)(a-b)

We have (-5x-3)(-5x+3)

Lets prove it:

(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)

(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)

(-5x-3)(-5x+3) = 25x^2-15x+15x-9

(-5x-3)(-5x+3) = 25x^2-9

(-5x-3)(-5x+3) = (5x)^2 - (3)^2

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The value of k is 6.
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Answer:

Step-by-step explanation:

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ahrayia [7]

Answer:

6 hope this was fast

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