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kirill [66]
3 years ago
11

Divide. (3 3/4 )÷(−2 1/2 ) Enter your answer as a mixed number, in simplified form, in the box.

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

-11/14

Step-by-step explanation:  first you divide 33/4 and (-21/2), then reduce the numbers to -33/4 times 2/21 after you reduce both fractions multiply -11/2 times 1/7 and you get -11/14 your alternative form would br -0.785714


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The workers at Cameron's Flower shop are putting 1,323 flowers into vases for a party .Each base must hold exactly 8 flowers .Wh
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Answer:

165

Step-by-step explanation:

How many complete vases can Cameron's Flower shop fill with 8 flowers each, considering they have a total of 1,323 flowers in total.

All you have to do is divide 1,323 by 8 to get = 165.375 or 165 and 3/8.

Since the question is about COMPLETE vases of 8 flowers, that means the answer is 165, and we don't count the 3 remaining flowers.

Good job Cameron!

3 0
3 years ago
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2 years ago
In which quadrant is (-1/2, -1.8)?
Anna71 [15]

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3 0
3 years ago
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How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

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3 years ago
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