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kirill [66]
3 years ago
11

Divide. (3 3/4 )÷(−2 1/2 ) Enter your answer as a mixed number, in simplified form, in the box.

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

-11/14

Step-by-step explanation:  first you divide 33/4 and (-21/2), then reduce the numbers to -33/4 times 2/21 after you reduce both fractions multiply -11/2 times 1/7 and you get -11/14 your alternative form would br -0.785714


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Pink floyd had a song named brain damage true or false
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Answer:

True

Step-by-step explanation:

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3 years ago
Write the expression as a single natural logarithm.3In3+3Inc
k0ka [10]

Answer:

ln(27c^3)

Step-by-step explanation:

Given: 3ln(3)+3ln(c)

If there is a coefficient in front of a log or ln, that means it becomes an exponent.

ln(3^3)+ln(c^3)

Simplify the exponent.

ln(27)+ln(c^3)

When there is addition between two logarithms or natural logarithms, it means they multiply together.

ln(27c^3)

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A line segment is defined as a part of a straight line connecting two points called
Feliz [49]

Answer: D

Step-by-step explanation:

7 0
3 years ago
Find the vertex of y=-x^2-4x
Kay [80]
The vertex would be (-2,4)
3 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
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