Answer: C
Step-by-step explanation:^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Answer:
(4, 1)
Step-by-step explanation:
Since the first reflection is over the vertical line x=-3, the y-coordinate remains the same. The x-coordinate of A' will make the point (-3, 4) on the line of reflection be the midpoint between A and A':
(-3, 4) = (A +A')/2
2(-3, 4) -A = A' = (-6-(-7), 8 -4) = (1, 4)
The reflection over the line y=x simply interchanges the two coordinate values:
A'' = (4, 1)
<h3>E
xplanation:</h3>
Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).
cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)
(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2
cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin
cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired
The amount that the bank loaned out at 7.9% is $1,574.00
How do represent the amounts lent at different rates?
On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate
interest on 7.9% loan=7.9%*x=0.079x
interest on 7.4% loan=7.4%*(8200-x)
interest on 7.4% loan=606.80-0.074x
total interest=0.079x+606.80-0.074x
total interest=0.005x+606.80
total interest on loans=614.67
614.67=0.005x+606.80
614.67-606.80=0.005x
7.87=0.005x
x=7.87/0.005
x=amount loaned at 7.9%=$1,574.00
y=$8200-$1574
y=$6,626.00
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