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attashe74 [19]
3 years ago
8

Help me with these problems please.

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0
Problem 18 would be he added 4 marbles to equal 10
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If CDE ~ GDF, find ED
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Answer:

10

Step-by-step explanation:

\triangle CDE \sim \triangle GDF.. (given) \\\\\therefore \frac{CD}{GD} =\frac{DE}{DF}.. (csst) \\\\\therefore  \frac{15}{x+3} =\frac{3x+1}{4}\\\\ \therefore   \: 15 \times 4 = (x + 3)(3x + 1) \\  \\ \therefore   \: 60 = 3 {x}^{2}  + x + 9x + 3 \\  \\ \therefore  3 {x}^{2}  + 10x + 3 - 60 = 0 \\ \therefore  3 {x}^{2}  + 10x  - 57 = 0 \\ \therefore  3 {x}^{2}  + 19x - 9x  - 57 = 0 \\ \therefore   \: x(3x + 19) - 3(3x + 19) = 0 \\\therefore   \:  (3x + 19)(x - 3) = 0 \\ \therefore   \: 3x + 19 = 0 \:  \: or \:  \: x - 3 = 0 \\  \therefore   \: x =  -  \frac{19}{3}  \:  \: or \:  \: x = 3 \\  \because \: x \: can \: not \: be \:  - ve \\ \therefore   \: x = 3 \\ ED = 3x + 1 = 3 \times 3 + 1  \\ \huge \red{ \boxed{ ED= 10}}

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