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3 years ago

11

The number of people and dogs taking in obedience class increased from 1800 students to 1600 student what is the percent increas

e

1 answer:

kolbaska11 [484]3 years ago

7 0

Increased or decreased?

I attached an image above of how to solve this equation.

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What is the product of (-a+3)(a+4)

spin [16.1K]

Answer:

-a^2 -4a +3a +12

-a^2 -1a +12

Step-by-step explanation:

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3 years ago

Would 20, 40, 30 form a right angle

Mashutka [201]

Yes because if you add forty and thirty that equals seventy plus twenty is 90 which is a right angle

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3 years ago

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In a jar of coins, 18 out of the 40 coins are dimes. Express the fraction of the coins

Step2247 [10]

Answer:

Percent: 20%

Fraction: 1/5

Decimal: 0.20

Step-by-step explanation:

8:40*100 =

( 8*100):40 =

800:40 = 20%

Percent to fraction:

20%=20/100

= 0.2

=0.2×10/10

=2/10

=1/5

Percent to decimal:

20/100 = 0.20

8 0

3 years ago

A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged

Alexxx [7]

Answer:

a) $E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

b) First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

c) $P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

d) $P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

$X \sim Unif (a= 100, b=1100)$

Part a

For this case the average is given by the expected value and we can use the following formula:

$E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

Part b

First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

$F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100$

And we can find this probability:

$P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

Part d

$P(311 < X< 889) = P(X$

And using the cdf we got:

$P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

6 0

3 years ago

Uma makes a scale drawing of a patio. The drawing below shows the two scales she used to plan two patios of different sizes.

Vinil7 [7]

Answer:

Scale 1: 45 m; Scale 2: 60 m

Explanation:

All you do is multiply 15 centimetres by each metre value on each scale to get the above scale.

* Now, you NEVER included expressions, but I did my very best to predict the above imagery.

I am joyous to assist you anytime.

4 0

3 years ago

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