Question

A 52-in TV measures 52 inches along its diagonal (corner to corner measure). If that TV is 33.6 inches high, how wide is it?

Answer 1

Answer:

1575.04

Step-by-step explanation:

Using Pythagoras theorem,

a^2+b^2=C^2

52^2-33.6^2=1575.04

Answer 2

Step-by-step explanation:

Use Pythagoras' theorem

${a}^{2} = b {}^{2} + c {}^{2}$

52² = 33.6² + x²

solve for x