A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!

Mathematics

1 answer:

mario62 [17]2 years ago

4 0

Answer:

$(x+1)(17a-1)$

Step-by-step explanation:

We are given that

$17ax+17a-x-1$

We have to factorize the given expression.

Pair up the terms

$(17ax+17a)+(-x-1)$

Now, taking common factor

$17a(x+1)-1(x+1)$

Taking common (x+1)

$(x+1)(17a-1)$

Now, we get

$(x+1)(17a-1)$

This is required factors of given expression.

You might be interested in

Please help its for today before 11

Black_prince [1.1K]

Alright, the zeroes are where it intersects with the X-axis so...

4) -15 and 10

5) 6 and 18

6) -5 and 0

7) -20 and -8

8) 2 and 10

9) -21 and 14

Hope I was able to help you :)

6 0

2 years ago

Multiple the binomials (x+3)^2

maxonik [38]

Answer:

$=x^2+6x+9$

Step-by-step explanation:

$\left(x+3\right)^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=x,\:\:b=3\\=x^2+2x\cdot \:3+3^2\\\mathrm{Simplify}\:x^2+2x\cdot \:3+3^2:\quad x^2+6x+9\\x^2+2x\cdot \:3+3^2\\\mathrm{Multiply\:the\:num\\bers:}\:2\cdot \:3=6\\=x^2+6x+3^2\\3^2=9\\=x^2+6x+9$