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3 years ago

How do i find the unknown side length of #9?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

4 0

You can find the unknown side length by using pythagorean theorem. a²+b²=c²
Simply plug-in numbers into the formula. Your answer is 80.

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Which is true 1) 31^3 12^10

aev [14]

Answer:

1,844,580,200,000,000 = 1.8445802×10^15

Step-by-step explanation:

31^3 x 12^10

31^3 = 31 x 31 x 31

12^10 = 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12

31^3 = 29791

12^10 = 61917364224

29791 x 61917364224 = 1,844,580,200,000,000 = 1.8445802×10^15

8 0

3 years ago

Read 2 more answers

Fit a quadratic function to these three points: (-2,8)(0,-4),and (4,68)

aev [14]

Given three points
P1(-2,8)
P2(0,-4)
P3(4,68)
We need the quadratic equation that passes through all three points.

Solution:
We first assume the final equation to be
f(x)=ax^2+bx+c .............................(0)

Observations:
1. Points are not symmetric, so cannot find vertex visually.
2. Using the point (0,-4) we substitute x=0 into f(x) to get
f(0)=0+0+c=-4, hence c=-4.
3. We will use the two other points (P1 & P3) to set up a system of two equations to find a and b.
f(-2)=a(-2)^2+b(-2)-4=8 => 4a-2b-4=8.................(1)
f(4)=a(4^2)+b(4)-4=68 => 16a+4b-4=68.............(2)
4. Solve system
2(1)+(2) => 24a+0b-12=84 => 24a=96 => a=96/24 => a=4 ......(3)
substitute (3) in (2) => 16(4)+4b-4=68 => b=8/4 => b=2 ..........(4)
5. Put values c=-4, a=4, b=2 into equation (0) to get

f(x)=4x^2+2x-4

Check:
f(-2)=4((-2)^2)+2(-2)-4=16-4-4=8
f(0)=0+0-4 = -4
f(4)=4(4^2)+2(4)-4=64+8-4=68
So all consistent, => solution ok.

6 0

4 years ago

1a simplify 6x × 3y

lesantik [10]

18xy
You need to do 6*3=18
Then x*y= xy

6 0

3 years ago

12/21 in its simplest form

UNO [17]

12/21 in its simplest form is 4/7.

To find this out we need to divide the numerator and denominator by the GCF of 12 and 21 which is 3.

12/21

12 ÷ 3 = 4
21 ÷ 3 = 7
4/7

12/21 in its simplest form is 4/7.

12/21 = 4/7

5 0

4 years ago

Read 2 more answers

Please I beg you help me

Elena L [17]

Answer:

Option D

Step-by-step explanation:

Going through the choices will help determine which option best simulates the random selection of a voter.

Flip a coin three times, and assign outcomes as follows: HHH, HHT, or HTH = Nava; HTT, THH, or THT = Jensen; TTH = Moretti, TTT = Chang.

Given that it is a random selection of the 4 candidates, it means the probability of choosing either one of them is equivalent. From the option, it can be found that Nava and Jensen have a higher chance of being voted than Moretti and Chang, which would not fit the criteria of being randomly selected.

Roll a number cube, and assign outcomes as follows: 1 or 2 = Nava, 3 or 4 = Jensen, 5 = Moretti, 6 = Chang.

Again, Nava and Jensen have a higher chance of being voted than Moretti and Chang. Therefore, this is not the correct option to simulate random selections of the 4 candidates.

Roll a number cube, and assign outcomes as follows: 1, 2, or 3 = Nava, 4 = Jensen, 5 = Moretti, 6 = Chang.

Nava has a higher chance of being voted, so this option does not fit the stimulation.

Flip a coin twice, and assign outcomes as follows: HH = Nava, HT = Jensen, TH = Moretti, TT = Chang

In this scenario, all 4 candidates have an equal chance of being voted, so this option would best simulate the random selection of a voter from the city.

Hope this helps :)

8 0

3 years ago