All categories

3 years ago

Find the curved surface area of a cylindrical tank of base radius 30 cm and height 2m

Mathematics

1 answer:

Sati [7]3 years ago

8 0

${\pink{\underline{\textsf{\textbf{Answer : }}}}}$

➡️ 37,680m² will be the curved surface area of the cylindrical tank.

${\purple{\underline{\textsf{\textbf{Explanation : }}}}}$

Given that, A cylindrical tank of base radius is 30cm and it's height is 2m or, 200cm

We need to find the curved surface area

<u>We know that</u>,

➩ Curves surface area of a cylinder = 2πrh

r (radius) = 30cm.

h (height) = 200cm.

Therefore,

➩ Curves surface area of a cylinder:

➩ 2 × 3.14 × 30 × 200

➩ 2 × 18,840

➩ 37,680 m² ans.

You might be interested in

Need some help with this

sergij07 [2.7K]

Answer:

gradient 1/2, y-intercept 9

Step-by-step exp

4 0

3 years ago

Read 2 more answers

On a piece of paper, graph f(x) 2x>3

adell [148]

Answer: jibjabjobjab it’s there

Step-by-step explanation:

6 0

2 years ago

Michaela pays her cell phone service provider $49.95 per month for 500 minutes. any additional minutes used cost $0.15 each. in

True [87]

75 additional minutes were used

$61.20-$49.95=$11.25

$11.25/$0.15=75 additional minutes

4 0

3 years ago

What is 17cm per min=how much mile per hour

dalvyx [7]

(centimeter/minute): 17
(miles per hour): 0.00633799

6 0

3 years ago

Read 2 more answers

Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write

morpeh [17]

Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

$\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]$

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]$

r3 = r3+2r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]$

r2 = r2*(-1/13)

$\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r1 = r1- r2*5

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r3 = r3+ r2*-3

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]$

r3 = r3*13/168

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]$

r2 = r2- r3*22/13

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

r2 = r2+ r3*6/13

$\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

Here you have a reduced array an therefore the answers to each variable are on each row:

$\left[\begin{array}{c}x\\y\\z\end{array}\right]$

8 0

3 years ago