Question

Find the restricted values of x. -1/8x-2

Answer 1

x = $\frac{1}{4}$ is the restricted value

the denominator of the fraction cannot be zero as this would make it undefined.

Equating the denominator to zero and solving gives the value that x cannot be

solve : 8x - 2 = 0 → 8x = 2 → x = $\frac{1}{4}$