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anyanavicka [17]
4 years ago
9

Find the restricted values of x. -1/8x-2

Mathematics
1 answer:
Dmitry [639]4 years ago
3 0

x = \frac{1}{4} is the restricted value

the denominator of the fraction cannot be zero as this would make it undefined.

Equating the denominator to zero and solving gives the value that x cannot be

solve : 8x - 2 = 0 → 8x = 2 → x = \frac{1}{4}


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