4 years ago

Find the restricted values of x. -1/8x-2

Mathematics

1 answer:

Dmitry [639]4 years ago

3 0

x = $\frac{1}{4}$ is the restricted value

the denominator of the fraction cannot be zero as this would make it undefined.

Equating the denominator to zero and solving gives the value that x cannot be

solve : 8x - 2 = 0 → 8x = 2 → x = $\frac{1}{4}$

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