Pleas help due to night
2 answers:
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Answer:
Kindly check attached picture
Step-by-step explanation:
Given the data :
1,4,4,5,5,7,8,8,10,11,11,11,14,15,16
The median (Q2) :
0.5(n + 1)th value
n = number of observations = 15
0.5(15 + 1)th value = 0.5(16) = 8th observation = 8
Q3:
0.75(n+1)th value = 0.75(16) = 12th observation = 11
Q1 :
0.25(n+1)th value = 0.25(16) = 4th observation = 5
Interquartile range (IQR) = (Q3 - Q1) :
11 - 5 = 6
MINIMUM VALUE IN DATASET = 1
MAXIMUM VALUE IN DATASET = 16
