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Zigmanuir [339]
3 years ago
5

Find the midpoint of the segment with the following endpoints (-10,-1) and (-6,7)

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

(-8 , 3)

Step-by-step explanation:

(x1 , y1)   (x2 , y2) = (-10 , -1) (-6 , 7)

\frac{-6-10}{2} ,  \frac{7-1}{2}   -6 is going to be my x1 and -10 my y1

                     7 is going to be my x2 and -1 my y2

(-8 , 3)

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Find the value of the expression 3d+5 when d=3
sergiy2304 [10]
3x3=9
9+5=14 hope this helps u
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Explain what is meant by a 100% decrease.
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Tilda buys a shirt for d dollars. She uses a $50 gift card and receives $22.50 in change Write an equation for this.
luda_lava [24]

Answer:

$50 - d = $22.50

Step-by-step explanation:

Since she's receiving a change, it means that d is smaller than $50, therefore, it will be deducted from it to give the change.

4 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Devaughn is 15 years younger than Sydney. The sum of their ages is 73. What is Sydney’s age?
Olegator [25]

Answer:

Sydney is 44 years old

Step-by-step explanation:

<u>Step 1:  Make a system of equations </u>

d = s - 15

<em>d + s = 73 </em>

<u>Step 2:  Plug in s - 15 for d in the second equation and solve </u>

s - 15 + s = 73

2s - 15 = 73 + 15

2s  / 2= 88 / 2

<em>s = 44 </em>

Answer:  Sydney is 44 years old

6 0
4 years ago
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