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3 years ago

Using long division to divide 3x^4-2x^3+x-1 by x^2-x-2

Mathematics

1 answer:

Paha777 [63]3 years ago

7 0

Check the picture below.

recall to put the dividend as well as the divisor in descending order, and to include any missing terms before the constant.

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What is 149x1007? because i am having troubles trying to figure out

solniwko [45]

Answer:

150043 Is the answer

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3 years ago

Casey has 281 tennis balls. She will put them in containers that hold 3 tennis balls. About how many containers will Casey use?

lisov135 [29]

Answer:

Step-by-step explanation:

If we have total around 281 items, and we can divide them into groups of 3.

We can make around 281/3 groups which is about 90

3 0

3 years ago

Read 2 more answers

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 252 miles in the same time that Dana travels 228 miles. I

vlada-n [284]

Answer:

Chuck's rate of travel = 63mph

Step-by-step explanation:

Given chuck travels 252 miles and dana travels 228 miles. Given that they both take same time to travel .

Let the travelling time be T.

Also given that the speed of chuck is 6mph greater than that of dana's.

let the speed of chuck be x. Now

Speed = $\frac{distance }{time}$

x= $\frac{252}{T}$

Now for Dana's speed

x-6= $\frac{228}{T}$

When we divide both the equations we get

$\frac{x}{x-6}=\frac{252}{228}$

$\frac{x}{x-6}=\frac{63}{57}$

x=63mph

7 0

3 years ago

Read 2 more answers

I need help with eight and nine you are to multiply the binominaals using the horizontal format

lorasvet [3.4K]

Answer:

8. $15m^2-31m+10\\$

9. $x^2y^2z^2+2xyz-3$

Step-by-step explanation:

$(a+b)(c+d)=ac+ad+bc+bd\\(3m-5)(5m-2)=3m*5m+3m(-2)-5*5m(-2)\\=3m*5m+3m(-2)-5*5m(-2)\\=15m^2-31m+10$

^#8^

$(xyz+3)(xyz-1)=xyzxyz+xyz(-1)+3xyz+3(-1)\\=xyzxyz+xyz(-1)+3xyz+3(-1)\\=x^2y^2z^2+2xyz-3$

^#9^

4 0

2 years ago

Suppose X and Y are random variables with joint density function. f(x, y) = 0.1e−(0.5x + 0.2y) if x ≥ 0, y ≥ 0 0 otherwise (a) I

Hatshy [7]

a. $f_{X,Y}$ is a joint density function if its integral over the given support is 1:

$\displaystyle\int_{-\infty}^\infty\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\frac1{10}\int_0^\infty\int_0^\infty e^{-x/2-y/5}\,\mathrm dx\,\mathrm dy$

$=\displaystyle\frac1{10}\left(\int_0^\infty e^{-x/2}\,\mathrm dx\right)\left(\int_0^\infty e^{-y/5}\,\mathrm dy\right)=\frac1{10}\cdot2\cdot5=1$

so the answer is yes.

b. We should first find the density of the marginal distribution, $f_Y(y)$ :

$f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\frac1{10}\int_0^\infty e^{-x/2-y/5}\,\mathrm dy$

$f_Y(y)=\begin{cases}\dfrac15e^{-y/5}&\text{for }y\ge0\\\\0&\text{otherwise}\end{cases}$

Then

$P(Y\ge8)=\displaystyle\int_8^\infty f_Y(y)\,\mathrm dy=e^{-8/5}$

or about 0.2019.

For the other probability, we can use the joint PDF directly:

$P(X\le5,Y\le8)=\displaystyle\int_0^5\int_0^8f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=1+e^{-41/10}-e^{-5/2}-e^{-8/5}$

which is about 0.7326.

c. We already know the PDF for $Y$ , so we just integrate:

$E[Y]=\displaystyle\int_{-\infty}^\infty y\,f_Y(y)\,\mathrm dy=\frac15\int_0^\infty ye^{-y/5}\,\mathrm dy=\boxed5$

5 0

3 years ago