Sum of linear pair of angles = 180°
so
<EFG + <GFH = 180°
2n + 21 + 4n + 15 = 180°
6n + 36 = 180°
6n = 144
n = 24
<EFG = 2(24) + 21 = 69°
<GFH = 4n + 15 = 4(24) + 15 = 111°
Answer:
100
Step-by-step explanation:
20 times 100 equals 2000
Answer:
![\frac{2}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B7%7D)
Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = ![\frac{1}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B7%7D)
Remaining fuel after driving around the city = 1 -
= ![\frac{7 - 1}{7} = \frac{6}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B7%20-%201%7D%7B7%7D%20%20%3D%20%5Cfrac%7B6%7D%7B7%7D)
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = ![\frac{6}{7} \div 3](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B7%7D%20%5Cdiv%203)
=![\frac{6}{7} \times\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B7%7D%20%5Ctimes%5Cfrac%7B1%7D%7B3%7D)
= ![\frac{6}{21}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B21%7D)
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
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Answer:
1st from the left
Step-by-step explanation: