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3 years ago

What is the square root of 704?

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

$\sqrt{704}=8\sqrt{11}$

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4 years ago

What is (8n^2-26n+20) divided by (n-2)?

Mama L [17]

Answer:

A. 8n-10

Step-by-step explanation:

8n2−26n+20/n−2

=2(4n−5)(n−2)/n−2

=8n−10

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3 years ago

Please answer these and find the slope intercept form for each one.

damaskus [11]

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3 years ago

Which shows the following expression after the negative exponents have been eliminated?

Mazyrski [523]

Answer:

$a^2b^2$

Step-by-step explanation:

Given the algebraic expression:

$\dfrac{a^3b^{-2}}{ab^{-4}} , a\neq 0, b\neq 0$

We are required to eliminate the negative exponents and find the resulting expression.

Using the Negative Exponent Law of Indices: $x^{-y}=\dfrac{1}{x^y}$

Using the Division Law of Indices: $\dfrac{t^x}{t^y}=t^{x-y}$

Therefore:

$\dfrac{a^3b^{-2}}{ab^{-4}} = a^{3-1}\cdot b^{-2-(-4)}\\$Simplifying\\a^{3-1}\cdot b^{-2-(-4)}=a^2b^{-2+4}\\=a^2b^2\\Therefore:\\\dfrac{a^3b^{-2}}{ab^{-4}}=a^2b^2$

7 0

3 years ago

Read 2 more answers

Ima Neworker requires 30 minutes to produce her first unit of output. If her learning curve rte is 65%, how many units will be p

Vilka [71]

Answer:

Approximately 18 units will be produced before the output rate exceeds 12 units per hour.

Step-by-step explanation:

The learning curve formula is given by:

$Y = aX^{b}$

In which:

Y is the average time per unit.

X is the cumulative number of units produced.

a is the time required to produe the first unit

b = log of learning rate/log 2

In our problem, we have:

Y = 12 units per hour. We are working in minutes, what is the average time per unit?

60 minutes - 12 units

Y minutes - 1 unit

$12Y = 60$

$Y = 5$

So Y = 5.

X is the value we want to find

a = 30

b = $\frac{log 0.65}{log 2}=-0.6215$

$Y = aX^{b}$

$5 = 30X^{-0.6215}$

$\frac{1}{6} = \frac{1}{X^{0.6215}}$

$X^{0.6215} = 6$

$\sqrt[0.6215]{X^{0.6215}} = \sqrt[0.6215]{6}$

$X = 17.86$

Approximately 18 units will be produced before the output rate exceeds 12 units per hour.

3 0

4 years ago