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AURORKA [14]
3 years ago
12

Find the value of x 12 5 X

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

x = 13

Step-by-step explanation:

Note that the side length x is opposite of the right angle, which means that it is the hypotenuse, which will usually be denoted as c.

Set the equation:

a² + b² = c²

let:

a = 5

b = 12

c = x

Plug in the corresponding numbers (& x) to the corresponding variables:

(5)² + (12)² = (x)²

Simplify. First, solve for the power, and then add:

x² = (5²) + (12²)

x² = (5 * 5) + (12 * 12)

x² = 25 + 144

x² =  169

Next, root both sides of the equation:

√x² = √169

x = √169 = √(13 * 13) = 13

x = 13

~

Note the rules, and it should be easier:

30-60-90° = 1 , √3 , 2

45-45-90° = 1 , 1 , √2

Any other measurements use the equation:  a² + b² = c²

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Step-by-step explanation:

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our product here is 20, so any product that gives 20 would be a good fit as the value of the width and length of the rectangle

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The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2
Stells [14]

The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

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This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

Learn more about computations on:

brainly.com/question/4658834

#SPJ4

Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

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