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morpeh [17]
3 years ago
6

Surface area of prisms

Mathematics
2 answers:
Lena [83]3 years ago
7 0

12x12=144. Answer is 144 miles

dybincka [34]3 years ago
5 0

Answer:

\boxed{\text{672 mi}^{2}}

Step-by-step explanation:

The formula for the surface area of a rectangular prism is

S = 2(lw + lh + wh)

Data:  

 l = 12 mi

w = 12 mi

h =   8 mi

Calculations:

2(Top + Bottom) = 2lw  = 2 × 12 × 12 = 288 mi²

2(Front + Back) = 2lh   = 2 × 12 ×   8 = 192 mi²

  2(Left + Right) = 2wh = 2 × 12 ×   8 = <u>192 mi² </u>

                                         Total area = 672 mi²

The surface area of the rectangular prism is \boxed{\textbf{672 mi}^{2}}

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Answer: 6.7 mm

Step-by-step explanation:

The area of a square is equal to side(side), but is also equal to 1/2(apothem)(perimeter).

The apothem is the perpendicular distance from the center of the square to the midpoint of its side.

We can use these formulas to find the apothem and use the pythagorean theorem to find the hypotenuse (slant height).

Area of square = 9(9) = 81

Area of square = 1/2(apothem)(perimeter)

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81 = 1/2(apothem)(36)

162 = apothem(36)

apothem = 4.5

Pythagorean theorem: a^{2} + b^{2}  = c^{2}

Plug the apothem and the given height into the equation:

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If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

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