What is the probability of drawing a jack from a standard deck of cards, replacing it,shuffling, then drawing an ace?
1 answer:
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Answer:
C(t) = I/F [1 - e^(-Ft/V) ] + C₀e^(-Ft/V)
as t = 0 ; C(t) = 1/F
Explanation:
dC/dt) = (-F/V)*C+(I/V)
To make it easier to solve, let
Constants: I, V,F
Variables: C, t
workings and solution can be viewed below
