Did I divided the polinoms in a correct way?<br>If I didn't please explain how

(14v^7x^2-3v^7x^5)divided by (-2v^4x^3)

Dmitrij [34]

.1 Simplify: 5n(2n3+n2+8)+n(4-n).

Solution:

5n(2n3+n2+8)+n(4-n).

= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.

= 10n4 + 5n3 + 40n + 4n – n2.

= 10n4 + 5n3 + 44n – n2.

= 10n4 + 5n3 – n2 + 44n.

Answer: 10n4 + 5n3 – n2 + 44n

5 0

3 years ago

Homework: Algebra Re<br> Find the slope and the y-intercept<br> 6x-7y=15

umka21 [38]

Answer:

the slope is 6/7 the y-intercept is (0, - $\frac{15}{7}$ )

Step-by-step explanation:

I'm not 100% sure sorry lol.

3 0

3 years ago

Read 2 more answers

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa

MakcuM [25]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

Step-by-step explanation:

Data given and notation

$X_{1}=25$ represent the number of homeowners who would buy the security system

$X_{2}=9$ represent the number of renters who would buy the security system

$n_{1}=140$ sample 1

$n_{2}=60$ sample 2

$p_{1}=\frac{25}{140}=0.179$ represent the proportion of homeowners who would buy the security system

$p_{2}=\frac{9}{60}= 0.15$ represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

6 0

3 years ago

Z ⊂ Q ⊂ Q ' <br> true or false

gavmur [86]

The answer is so false

3 0

1 year ago

Which statement best describes the function below?

12345 [234]

The answer is B
Because when you graph it in the calculator you get x=-136 and that goes to one to one function on the graph

5 0

3 years ago

Did I divided the polinoms in a correct way?If I didn't please explain how ​

Did I divided the polinoms in a correct way?If I didn't please explain how