Answer:
can you explain yourself more please
The graph is the one with coordinates (1,2) as the center.
Answer:
D
Step-by-step explanation:
You just need to calculate it as usual. Might as well do in fraction form for clearer understandings
Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
Answer:
r³ + 15r² - 10r - 4
Step-by-step explanation:
First, note you can remove the brackets, in this case they contribute nothing at all.
Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.
Finally, order them from greatest power of r to smallest power of r.
That's all!