Answer:
-37/6
Step-by-step explanation:
A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
Answer:
A. (2,2), (3,2), (3,3), (3,4), (4,6), (5,4), (5,7), (6,4), (6,6), (7,7)
32 is ur answer
sorry if its wrong
Im bad at this
The coefficient of b is h/2. Multiply the equation by the reciprocal of that.
(2/h)A = (2/h)·(h/2)·b
b = 2A/h . . . . . simplify