Which is perpendicular to the line y=-3x-8y

Mathematics

2 answers:

Sonbull [250]2 years ago

6 0

Answer:

Step-by-step explanation:

Find the Slope of a Perpendicular Line

y = −3x − 8y

Rewrite in slope-intercept form.

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

y = mx + b

Move all terms containing y to the left side of the equation.

9y = −3x

Divide each term by 9 and simplify.

y = −(x/3)

Write in y = mx + b form.

y = -(1/3)x

Using the slope-intercept form, the slope is − (1/3)

m = -(1/3)

The equation of a perpendicular line to y = − (1/3)x must have a slope that is the negative reciprocal of the original slope.

$m$ perpendicular = $-\frac{1}{-\frac{1}{3} }$

Simplify the result.

$m$ perpendicular = 3

atroni [7]2 years ago

4 0

Answer:

I believe the answer is y = -7/3x

Step-by-step explanation:

When you rearrange the equation, y = -3x - 8y, you will get -7y = -3x.

We want the equation to be equal to y by itself. So we divide -7 from both sides, giving us the equation y = 3/7x.

The graph that is perpendicular to y = 3/7x is it's reciprocal: y = -7/3x

You might be interested in

Show work to above problem

Len [333]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
|a|\implies 
\begin{cases}
+a\\
-a
\end{cases}\implies \pm a\\\\
-------------------------------\\\\
(16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x
\\\\\\
\begin{cases}
+4\\
-4
\end{cases}\implies |4x|$