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3 years ago

3/10 in.=7/8 mi. (i am doing rates and ratios)

Mathematics

1 answer:

harkovskaia [24]3 years ago

5 0

3/10 in
1 in =(1/12)ft 
1 ft =(1/5280) mi 

3/10 in=3/10*(1/12)*(1/5280) mi

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Sadie simplified the expression √54a^7b^3, where a>=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b

Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote $a^7$ as $a^2 * a^5$ instead of $a^6 * a$ .

The square root of $a^6$ is $a^3$ and so she could have further simplified.

The correct simplification is shown below:

$\sqrt{54a^7b^3} = \sqrt{2 * 3 * 3 * 3 * a^6 * a * b^2 * b} \\ \\= \sqrt{3^2 * a^6 * b^2 * 6 * a * b} \\\\= 3a^3b\sqrt{6ab}$

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hodyreva [135]

Given Information :-

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A polygon with 10 sides ( Decagon )

⠀

To Find :-

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The value of one of the exterior angles

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Formula Used :-

⠀

$\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star$

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Solution :-

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Putting the given values, we get,

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$\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\$

Thus, the value of the exterior angles of a Decagon is 36°.

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$\underline{ \rule{227pt}{2pt}} \\ \\$

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