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I need help with this question???

Sholpan [36]

Answer:

A

Step-by-step explanation:

Because -20 is more than -17 by -3

6 0

3 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

A=152

7 0

3 years ago

Which line is parallel to a line that has a slope of 3 and a y-intercept at (0, 0)?

saul85 [17]

Answer:

HJ

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

so

The slope of the line that is parallel to a line that has a slope of 3 is equal to 3

Verify the slope of the blue and red line , because their slopes are positive

Blue line

we have

C(-3,0),D(3,2)

The slope m is equal to

m=(2-0)/(3+3)

m=2/6

m=1/3

Red line

we have

H(-1,-4),J(1,2)

The slope m is equal to

m=(2+4)/(1+1)

m=6/2

m=3

therefore

The answer is the red line HJ

4 0

3 years ago

Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.

noname [10]

Hey!

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They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

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Hence, the answer is $\Large\boxed{\mathsf{y~=~8x~+~-26}}$

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Hope This Helped! Good Luck!

4 0

3 years ago

The equation 12x² + 4kx + 3 = 0 has real and equal roots, if

sleet_krkn [62]

Answer:

$k=\pm3$

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant $\Delta = b^2-4ac$ (or, if b is an even number, 1/4 of it) is zero.

I see it! I see it!

Stare at it for a while. First term is $3(2x)^2$ , third term is $3(1)^2$ , we are missing a double product, but we can play with k. For the LHS to be $3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3$ you just need $4k= \pm12 \rightarrow k=\pm3$ .

I don't see it...

Then number crunching it is. Set the discriminant to 0, solve for k

$\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3$

8 0

2 years ago