40 fifth graders went to a school trip 25%of the students went to see the space exhibit how many students is that
2 answers:
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Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
First option and Fourth option.
Step-by-step explanation:
To solve this exercise you need to use the following Trigonometric Identity:
In this case you know that:
Since triangle ABC is similar to triangle DEF:
Let's begin with the triangle ABC.
You can identify that:
Then, substituing values, you get:
In triangle DEF, you know that:
So, substituing values, you get: