Ask question

Ask question

All categories

kakasveta [241]

2 years ago

14

Which statement is true about the function f(x)= squared root negative x?

1 answer:

Liono4ka [1.6K]2 years ago

4 0

The answer is the first option: it has the same domain as the function f(x) = - √(-x).

The domain is the set of x-values for which the function is defined.

The square root function is defined only for zero and positve values.

- x is positive when x negative.

So the domain for - √(-x) and √(-x) are the same: x less than or equal to zero.

You might be interested in

In the triangle ?ABC, with side a = 5,<br>7.51<br>G<br>2.97<br>оо<br>5.71<br>7.15<br>O<br>O<br>4.14

icang [17]

Yes i is the time of the day you get to frost the moon and back and then you can come over and then go to hang out with me me and then go to hang out over www

5 0

3 years ago

Find the value of k.

Hoochie [10]

Answer:

It is 10

Step-by-step explanation:

4 0

2 years ago

Which table represents a linear function with a greater y-intercept than that of the function represented in the graph?

Thepotemich [5.8K]

Answer:

Table #3

Step-by-step explanation:

hope it helps

4 0

3 years ago

Read 2 more answers

HELP ME NUMBER 7 & 8 Not Number 6 <br> (For number 7 you have to divide

Sauron [17]

The one that starts with the girl named katherine is 60.54

3 0

3 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

<em>1364</em> is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

<em>1. 5 digit numbers:</em>

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

<em>2. 4 digit numbers:</em>

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

<em>3. 3 digit numbers:</em>

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

<em>4. 2 digit numbers:</em>

We have <em>2</em> places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

<em>5. 1 digit numbers:</em>

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = <em>1364</em>

3 0

2 years ago