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Sladkaya [172]
2 years ago
13

um dado de 6 faces numeradas de 1 a 6 e lançado de maneira aleatória deseja-se que ele caia com uma face para cima . Qual a prob

abilidade de se obter a face com um dos valores desejados​
Mathematics
1 answer:
Mazyrski [523]2 years ago
5 0

Answer: The translation: is "a die with 6 faces numbered from 1 to 6 and thrown in a random way is desired to fall face up. What is the probability of obtaining the face with one of the desired values"

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Please help me find y and show work/steps. I don't know how to do it
trasher [3.6K]

We will check if y and 60cm are parallel.

If the lengths 28cm, 56cm and 15cm, 30cm are in proportion, then y and the segment 60cm are parallel.

\dfrac{56}{28}=\dfrac{30}{15}\\\\2=2\qquad CORRECT!

OK. We know: y and 60cm are parallel. Therefore we have equation:

\dfrac{y}{28+56}=\dfrac{60}{56}\\\\\dfrac{y}{84}=\dfrac{15}{14}\qquad|\text{cross multiply}\\\\14y=15\cdot84\qquad|\text{divide both sides by 14}\\\\y=90cm

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P ( m ) = 0.82
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