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Sladkaya [172]
3 years ago
13

um dado de 6 faces numeradas de 1 a 6 e lançado de maneira aleatória deseja-se que ele caia com uma face para cima . Qual a prob

abilidade de se obter a face com um dos valores desejados​
Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer: The translation: is "a die with 6 faces numbered from 1 to 6 and thrown in a random way is desired to fall face up. What is the probability of obtaining the face with one of the desired values"

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How do I solve this problem
Brums [2.3K]

Answer:

a =9

b= 28

Step-by-step explanation:

The parts of the ratio must be equal

5:7:a = 20:b:36

How do we get from 5 to 20

We multiply by 4

So multiply the first by 4

5*4:7*4:a*4 = 20:b:36

Ratio 1

5*4 =20  true

Ratio 2

7*4 =b

28 = b

Ratio 3

4a = 36

Divide by 4

4a/4 = 36/4

a = 9

4 0
3 years ago
Math help please show work thanks
Rufina [12.5K]

Answer:

The curve surface area(CSA) of a cylinder is 2πrh.

Since diameter=1.5 in.

          radius=diameter/2

                     =1.5/2 in.

                     =0.75 in.

And, the height of the bottle is 5 in.

Now,

CSA=2πrh

       =2π*0.75*5 in^2

       =15π/2 or 23.56 in^2

The size of the label needed to cover the entire bottle is 15π/2 or 23.56 in^2.

4 0
3 years ago
FREE POINTS
Nonamiya [84]
2 please pick me!!!!
5 0
4 years ago
Read 2 more answers
A university found that 25% of its students withdraw without completing the introductory statistics course. Assume that 30 stude
Morgarella [4.7K]

Answer:

0.0106 = 1.06% probability that 2 or fewer will withdraw

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they withdraw, or they do not. The probability of an student withdrawing is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

25% of its students withdraw without completing the introductory statistics course.

This means that p = 0.25

Assume that 30 students registered for the course.

This means that n = 30

Compute the probability that 2 or fewer will withdraw:

This is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{30,0}.(0.25)^{0}.(0.75)^{30} = 0.0002

P(X = 1) = C_{30,1}.(0.25)^{1}.(0.75)^{29} = 0.0018

P(X = 2) = C_{30,2}.(0.25)^{2}.(0.75)^{28} = 0.0086

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0002 + 0.0018 + 0.0086 = 0.0106

0.0106 = 1.06% probability that 2 or fewer will withdraw

8 0
3 years ago
Rewrite in simplest terms: (x+10y)-(x+5y)(x+10y)−(x+5y)
Solnce55 [7]

Answer:

-x^2-15xy-50y^2+14y

Step-by-step explanation:

3 0
3 years ago
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