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PSYCHO15rus [73]

4 years ago

15

The wholesale price for a shirt is $6.50. A certain department store marks up the wholesale price by 60% . Find the price of the

shirt in the department store. Round your answer to the nearest cent, as necessary.

1 answer:

statuscvo [17]4 years ago

5 0

3.90 I’m not really sure though

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Which of the following could be the equation for a parabola that opens to the left with vertex (-17,2)?

Gemiola [76]

Answer:

C

Step-by-step explanation:

Just plugging in the given x or y values, you can rule out both A and B, only C and D work out logically.

-17=-3(2-2)²-17

-17=0-17

-17=-17✓

2=3(x+17)1+2

2=0+2

2=2✓

With parabolas, if you're talking in terms of y=x², it will be vertical. If talking in terms of x=y², it will be horizontal. As we're looking for something horizontal (open to the left), we need a x=y² formula. Of C and D, only C is an x=y² formula, and thus the answer.

7 0

3 years ago

38% of blank peaches is 19 peaches.

Igoryamba

Answer:

50

Step-by-step explanation:

38% of x= 19

38/100 * x= 19

38x=19*100

x=1900/38

x=50

3 0

3 years ago

Solve the system of linear equations by substitution. y−x=0y−x=0 2x−5y=9

Naddik [55]

There are no solutions to 2x-5y=9 but if you are solving it by y=mx+b form than your answer would look like this: y=2/5x-9/5

6 0

4 years ago

What is X equal to.<br> __I__<br> X 1<br> X 1<br> 1

uysha [10]

X is equal to X 1 because you would multiply x by 1 which would be x

7 0

3 years ago

he Nassau Bahamas Community College (NBC) claims that students who take statistics spend on average 19 hours a week working. The

Virty [35]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value</u> for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

At the null hypothesis, it is <u>tested if they spend on average 19 hours a week working</u>, that is:

$H_0: \mu = 19$

At the alternative hypothesis, it is <u>tested if they spend more than 19 hours a week working</u>, that is:

$H_1: \mu > 19$

We have the <u>standard deviation for the sample</u>, hence, the <em>t-distribution</em> is used.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Searching the problem on the internet, it is found that the values of the <em>parameters </em>are:

$\overline{x} = 24.2, \mu = 19, s = 12.59, n = 25$

Hence, the value of the <em>test statistic</em> is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.2 - 19}{\frac{12.59}{\sqrt{25}}}$

$t = 2.07$

The critical value for a <u>right-tailed test</u>, as we are testing if the mean is greater than a value, with a <u>significance level of 0.05</u> and 25 - 1 = <u>24 df</u> is of $t^{\ast} = 1.71$

Since the <u>test statistic is greater than the critical value</u> for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0

3 years ago