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aksik [14]
4 years ago
13

Solve the system of linear equations by substitution. y−x=0y−x=0 2x−5y=9

Mathematics
1 answer:
Naddik [55]4 years ago
6 0
There are no solutions to 2x-5y=9 but if you are solving it by y=mx+b form than your answer would look like this: y=2/5x-9/5
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Is this statement always, sometimes, or never true.
cestrela7 [59]

Answer:

Never true

Step-by-step explanation:

Linear angles are adjacent angles whose sum is 180

3 0
3 years ago
The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.
saveliy_v [14]
The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles, 
so
angle ACE is ----------> (90°-64°)-----------> 26° 
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

 The diagonals are angle bisectors to the opposite corners
so 
ACD = ACB = 52° 
and 
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so 
BAD = BCD = 104°

the answer is 
angle BAD=104°

3 0
3 years ago
HELP ASAP PLZ HELP<br> I will give a brain list if it is right !!! <br> just help me plz
lilavasa [31]
Answer: A

Explanation:
First you have to write the model in an equation form.

6x+5=15

Subtract 5 from both sides

6x=10

Divide 6 from both sides

X=10/6

Simplify

X=5/3 or 1.67
8 0
3 years ago
Read 2 more answers
Can someone please help with this trig question?
atroni [7]
First we must understand how to write a logarithmic function:

log_{b}a=x

In the equation above, b is the base, x is the exponent, and a is the answer. These same variables can be rearranged to be expressed as an exponential equation as followed:

b^x=a

Next, we need to understand basic logarithm rules.

1. When a value is raised to a power, we can move the exponent to the front of the logarithm. Example:

log(a^2) = 2log(a)

2. When two variables are multiplied together, we can add the logarithms of the individual variables together. Example:

log(ab) = log(a) + log(b)

3. When a variable is divided by another variable, we can subtract the logarithms of the individual variables. Example:

log(a/b) = log(a) - log(b)

Now we can use these rules to solve the problem.

log(r)=log( \sqrt[3]{ \frac{A^2B}{C} } )

We can rewrite the cube root as:

log(r) = log( (\frac{A^2B}{C})^ \frac{1}{3} )

Now we can move  the one-third to the front:

log(r) =  \frac{1}{3} log( \frac{A^2B}{C} )

Now we can split up the logarithm:

log(r) =  \frac{1}{3} (log(A^2)+log(B)-log(C))

Finally, we can move the exponent to the front of the log of A:

log(r) = \frac{1}{3} (2log(A)+log(B)-log(C))

Distribute the one-third to get the answer:

log(r) = \frac{2}{3} log(A) +  \frac{1}{3} log(B) -  \frac{1}{3} log(C)

The answer is (4).


3 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
fenix001 [56]

Answer:

x^6y^3

Step-by-step explanation:

<u>Given polynomial:</u>

  • 8x^6y^5 - 3x^8y^3

<u>Get prime factors:</u>

  • 2*2*2*x*x*x*x*x*x*y*y*y*y*y - 3*x*x*x*x*x*x*x*x*y*y*y

<u>Common factors of the two terms:</u>

  • x*x*x*x*x*x*y*y*y = x^6y^3

<u>So</u>

  • x^6y^3(8y^2 - 3x^2)

x^6y^3 is the GCF of this polynomial

4 0
3 years ago
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