Ignoring the "?" in your question:
![5k+10k+6=0 \iff 15k+6=0 \iff k=-\dfrac{6}{15}](https://tex.z-dn.net/?f=5k%2B10k%2B6%3D0%20%5Ciff%2015k%2B6%3D0%20%5Ciff%20k%3D-%5Cdfrac%7B6%7D%7B15%7D)
If the "?" is a squared symbol that wasn't caught:
![5k^2+10k+6=0](https://tex.z-dn.net/?f=5k%5E2%2B10k%2B6%3D0)
Use the quadratic formula
![x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
to get the solutions:
![x_{1,2}=\dfrac{-10\pm\sqrt{100-120}}{10}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cdfrac%7B-10%5Cpm%5Csqrt%7B100-120%7D%7D%7B10%7D)
as you can see, the discriminant is negative, so the equation has no solution.
The rock's height is increasing in the interval from 0 seconds to 3 seconds.
At time 0 the rock starts moving upward from 52 foot until it reachs 180 foot height (time 3 seconds). Then the rock starts to descend, which means that the height starts to decrease.
The way you round is if it is below 5 you round down and if it is above 5 you round up so in the case of 750 it would go to 800 where if it was 749 it would go to 700
Answer:
∠ ABC = 116°
Step-by-step explanation:
Since the angles are supplementary, they sum to 180° , that is
8x - 36 + 4x - 12 = 180
12x - 48 = 180 ( add 48 to both sides )
12x = 228 ( divide both sides by 12 )
x = 19
Then
∠ ABC = 8x - 36 = 8(19) - 36 = 152 - 36 = 116°
5-(n-4)=3(n+2)
5-n+4=3n+6
9-n=3n+6
3=4n
n=3/4