:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
Answer:
I think thats false
Step-by-step explanation:
Tell them false there isn't much evidence and if you tried to search it up thats not correct or the correct way to solve it theyre trying to trick you.
Answer:
The vertex Q' is at (4,5)
Step-by-step explanation:
Given:
Quadrilateral PQRS undergoes a transformation to form a quadrilateral P'Q'R'S' such that the vertex point P(-5,-3) is transformed to P'(5,3).
Vertex point Q(-4,-5)
To find vertex Q'.
Solution:
Form the given transformation occuring the statement in standard form can be given as:
The above transformation signifies the point reflection in the origin.
For the point P, the statement is:
So, for point Q, the transformation would be:
Since two negatives multiply to give a positive, so, we have:
You would set them equal to each other X= 13
Answer:
A. 61 degrees
Step-by-step explanation:
tan x = 9/5
x≈60.9
