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Ostrovityanka [42]
3 years ago
14

A total of $150000 is invested in two funds paying 6.25% and 6% simple interest. If the total interest for the year is $9212.50,

how much is invested at each rate?
Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

  • $85,000 at 6.25%
  • $65,000 at 6.00%

Step-by-step explanation:

Let x represent the amount invested at 6.25%. Then the total interest earned is ...

  0.0625x + 0.0600(150,000 -x) = 9212.50

  0.0025x = 212.50 . . . . . . subtract 9000, collect terms

  x = 212.50/0.0025 = 85,000

  150,000 - 85,000 = 65,000 . . . . amount invested at the lower rate

$85,000 is invested at 6.25%; $65,000 is invested at 6%.

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The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width , what are the dimensions?
lianna [129]
Let the length be \ell and the width be w. Now, write the length in terms of the width. "The length is 15 cm. less than twice the width" in the form of an equation is

\ell = 2w - 15 cm.

Let's plug that into the equation for the perimeter now. The perimeter of a rectangle is 2 \ell + 2w, so the equation for the perimeter of this rectangle is

2 \ell + 2w = 102 cm.

Plugging in the length in terms of width and solving for the width, we get

2(2w - 15 cm.) + 2w = 102 cm.
6w - 30 cm. = 102 cm.
6w = 132 cm.
\bf w = 22 cm.

To find the length, we just have to plug in the width into the equation we wrote for the length in terms of the width:

\ell = 2w + 15 cm.
\ell = 2(22 cm.) - 15 cm.
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