Answer:
x = 1 y = 3 z = 1
Step-by-step explanation:
(1) x - 3y - z = -9 (2) -2x + y + 2z = 3 (3) 2x + y + 3z = 8
2x(1) <u>2x - 6y - 2z = -18</u> (2) <u>-2x + y + 2z = 3</u>
- 5y = -15 2y + 5z = 11
y = 3 2(3) + 5z = 11
6 + 5z = 11
5z = 5
z = 1
x - 3(3) - 1 = -9
x - 9 - 1 = -9
x - 10 = -9
x = 1
Note: If you write your equations across your paper, then the work can just flow down the paper. It makes it so much easier to show the work you have done. OK?
Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
7-2=5
17-16=1
You are trying to find the difference that equals 3 and is near those range of numbers.
The numbers are 11 and 14.
