Taking point (0,-2) of graph one and replacing in the equation;
2x+3y=6
2(0)+3(-2)=6
-6=6
So graph isn't the required graph.
Taking point (0,2) of graph 2;
2x+3y=6
2(0)+3(2)=6
6=6
So, graph 2 is the required graph.
Area of a circle = (3.14) * r^2
d = 7
r = 3.5
a = (3.14) * 3.5^2
a = (3.14) * 12.25
a = 38.47
Just multiply the given x values by the function rule, that’s how you get ur y
Answer:
![-5x-5](https://tex.z-dn.net/?f=-5x-5)
Step-by-step explanation:
original functions:
![f(x)=3x-8\\g(x)=8x-3](https://tex.z-dn.net/?f=f%28x%29%3D3x-8%5C%5Cg%28x%29%3D8x-3)
Subtract the polynomials:
![f(x)-g(x) = (3x-8) - (8x-3)](https://tex.z-dn.net/?f=f%28x%29-g%28x%29%20%3D%20%283x-8%29%20-%20%288x-3%29)
Distribute the negative sign:
![3x-8-8x+3](https://tex.z-dn.net/?f=3x-8-8x%2B3)
Combine like terms:
![(3x-8x)+(-8+3)](https://tex.z-dn.net/?f=%283x-8x%29%2B%28-8%2B3%29)
Add like terms:
![-5x-5](https://tex.z-dn.net/?f=-5x-5)