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fenix001 [56]
3 years ago
14

In the expression below, a is an integer. 12^3+ax-20 if 3x+4 is a factor of the expession above, what is the value of a

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Our function is:

f(x)=12^3+ax-20

Now, if 3x+4 is a factor of f(x) then x=\frac{-4}{3} must satisfy the equation:

So, f(\frac{-4}{3} )=0

Putting x=\frac{-4}{3}

We get,

f(\frac{-4}{3} )=12^3+a(\frac{-4}{3} )-20=0

12^3+\frac{-4}{3} a-20=0

\frac{-4}{3} a=20-12^3=20-1708

a=-1708 \times \frac{-3}{4} =1281

So, the value of 'a' for the given expression is 1281.

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Answer:

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Step-by-step explanation:

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