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damaskus [11]
3 years ago
15

The price of an item has been reduced by 45% . The original price was $17

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0
Price is reduced by 45%. Which means that the new price is 55% of the original.
Therefore, (55/100)*17 = $9.35 =new price
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The graph of a function is f(x)=3√x.
suter [353]

Answer:

F(0.75)= 3/2 sq. root 3

F(9)= 9

F(7)= 3 sq. root 7

b) x= +-1

x=+-4

x= +- 49/9

3 0
2 years ago
Given the similarity statement<br> AJKL ANOP, what's the<br> corresponding side of ON ?
levacccp [35]

Answer:

ON = KJ

Step-by-step explanation:

JKL = NOP

We know the angles match

<J = <N

<K = <O

< L = <P

And we know

JK = NO

KL =  OP

JL = NP

We are looking for ON = KJ

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Henry swims at 1.6 laps per minute, Larry swims at 1.8 laps per minute. Larry swims faster
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3 years ago
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

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3 years ago
Evaluate f(x) = 8.4x + 3.8 when x = 9.1. Type the number only for auto grade to work correctly. Round your answer to 2 decimal p
vova2212 [387]
The answer is 80.24.
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