Answer:
![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
![\sqrt[4]{\sqrt[3]{2^2}} =((2^2)^\frac{1}{3})^\frac{1}{4}\\\\=(2^2)^\frac{1}{12}\\\\=2^\frac{2}{12}\\\\=2^\frac{1}{6}\\\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%20%3D%28%282%5E2%29%5E%5Cfrac%7B1%7D%7B3%7D%29%5E%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%3D%282%5E2%29%5E%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B2%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
Here is the answer in comma-separated list.
(5, 10) , (10,15), (15, 20) (20, 25) (25, 300 (30, 35)
You need 5 dimes while having 10 or 25
The answer is F=ma
In this type of equation, By followng, the rules that learned through aljabar ,
ab = ab
-ab = -ab
putting two letter representations will equal to multiplying it.Beside this, Putting a dot between each the two-letter representations will also indicate multiplication.
Answer:
(-1, 7)
Step-by-step explanation:
2 unites left would movie from 1 to -1.
1 unit down would move from 8 to 7.
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625