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tiny-mole [99]
2 years ago
9

ABCD is a rectangle, with M the midpoint or BC and N the midpoint of CD. If CM=4 and NC=5, what percent of the area of the recta

ngle is shaded
Mathematics
1 answer:
svp [43]2 years ago
6 0

Answer:

87.5%

Step-by-step explanation:

Given:

  • ⇒ ABCD is a rectangle, with M the midpoint of BC and N the midpoint of CD.
  • ⇒ CM = 4 and NC = 5.

Area of triangle NCM

⇒ 1/2 × base × height

⇒ 1/2 × CN × CM

⇒ 1/2 × 5 × 4

⇒ 10cm²

Length of rectangle ⇒ 10

Breadth of the rectangle ⇒ 8

↓

Area of rectangle ⇒ Length × Breadth

Area of rectangle ⇒ 10 × 8 = 80cm²

Area of shaded region ⇒ Area of rectangle  -  Area of triangle

Area of shaded region ⇒ 80 - 10 = 80cm²

Percentage of the shaded region = Shaded/complete rectangle × 100

⇒ 70/80 × 100 = 87.5

⇒ The percent of the area of the rectangle shaded is therefore 87.5%.

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