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Vikki [24]
3 years ago
9

The speed of sound in air is approximately 350 m/s. You are sitting in a canyon with cliffs 525 m from you. You clap your hands.

How long a delay is it to hear an echo of the clap?
Physics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

3 s.

Explanation:

Echo is defined as the repetition of a sound produced by the reflection of sound waves from an obstructing surface like a wall, mountain etc.

v = f*lambda

Where,

Lambda = wavelength of the wave

f = frequency of the wave = 1/t

v = velocity of the wave.

Distance there and back = initial ditance * 2

= 525 x 2

= 1050.

Time taken, t = lamda/velocity

= 1050 / 350

= 3 s.

So the delay is 3 seconds.

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An electron in a cathode-ray beam passes between 2.5cm long parallel-plate electrodes that are 6.0mm apart. A 2.1mT, 2.5-cm-wide
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Answer:

(a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2\ cm

Explanation:

Given that,

Length = 2.5 cm

Distance = 6.0 mm

Magnetic field = 2.1 T

Potential difference = 700 V

(a). We need to calculate the electron's speed

Using formula of speed

v=\sqrt{\dfrac{2eV}{m}}

Put the value into the formula

v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times700}{9.1\times10^{-31}}}

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v=1.56\times10^{7}\ m/s

(b). We need to calculate the radius of electron

Using formula of centripetal force

\dfrac{mv^2}{r}=qvB

r=\dfrac{mv}{qB}

Where,

m = mass of electron

v = speed of electron

r = radius

q = charge of electron

B = magnetic field

Put the value into the formula

r=\dfrac{9.1\times10^{-31}\times1.56\times10^{7}}{1.6\times10^{-19}\times2.1\times10^{-3}}

r=0.042\ m

r=4.2\ cm

Hence, (a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2 cm

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