All categories

3 years ago

How do gases respond to changes in pressure and temperature?

Physics

2 answers:

kakasveta [241]3 years ago

6 0

They compress or expand depending on amount of pressure or depending on the temperature

Darya [45]3 years ago

6 0

Answer:

<h2>The way gas responds to changes in temperature and pressure is the fundamental driver of motion in the atmosphere. The increase in volume can result in a decrease in pressure less frequent molecular collisions. As a result, the air mass is now less dense than adjacent air that was heated less.</h2>

Explanation:

You might be interested in

Can anyone help me with this??? Anyone familiar with this sorta project??

SIZIF [17.4K]

yah set up an experiment do u have the rocks with u?

7 0

3 years ago

the light from andromeda galaxy takes about 2.6 million years to reach earth. which of these statements is correct about the and

-Dominant- [34]

A. it is <span>located at a distance of 2.6 million light years from earth</span>

7 0

3 years ago

Why may some young adults go through a quarter-life crisis?

slavikrds [6]

Stress. Being alone. having nothing

6 0

3 years ago

Which of the following would be a good question that could be scientifically investigated? What is the best advice a parent can

Nesterboy [21]

<span>"Does lack of sunlight affect plant growth?"

This question can be investigated with procedures according to
the Scientific Method, because "lack of sunlight" can be arranged
unambiguously, and "affected plant growth" can be identified
unambiguously.

The other questions involve words or phrases with ambiguous definitions,
that can mean different things to different people, and would be hard to
agree on, like "</span><span>best advice", "sound quality", and "happiness in life".</span>

4 0

3 years ago

Read 2 more answers

what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three

grin007 [14]

Answer:

Approximately $5.11 \times 10^{-19}\; {\rm J}$ .

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: $R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}$ .

Look up the speed of light in vacuum: $c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}$ .

Look up Planck's constant: $h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}$ .

Apply the Rydberg formula to find the wavelength $\lambda$ (in vacuum) of the photon in question:

$\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}$ .

The frequency of that photon would be:

$\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}$ .

Combine this expression with the Rydberg formula to find the frequency of this photon:

$\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}$ .

Apply the Einstein-Planck equation to find the energy of this photon:

$\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}$ .

(Rounded to three significant figures.)

6 0

2 years ago