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dybincka [34]
3 years ago
5

the eagle trucking company must deliver 7/8 ton of cement blocks and 5/8 ton of bricks how much will this load weigh?

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0
This load will weigh 1.5 TONS ALTOGETHER.

So, the truck is delivering a \frac{7}{8} ton of cement blocks, and a \frac{5}{8} of bricks. To find how much this load weighs, we'd have to add the two fractions together, which proves to be quite easy, because the denominators are already the same, so we wouldn't have to change anything.

\frac{7}{8} + \frac{5}{8} = \frac{12}{8}

And now, we would want to convert that fraction into a whole number, or at least a decimal, to find how many tons the truck is carrying. So we would divide. Once the work is done, here is what would happen:

12 ÷ 8 = 1.5

And there's your answer. The truck is carrying 1.5 TONS.
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575 mL = how many Liters​
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Step-by-step explanation:

1mL = 0.001L

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3 years ago
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N a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly s
algol [13]

Answer: The probability that the player selects a card with S or E, a tile with 2 and a red disc is given as 0.125 (or 1/8)

Step-by-step explanation: If four cards are labelled N, S, E and W, then that means there are a total of four possible outcomes. Also with tiles numbered 1 and 2 there are a total of two possible outcomes when selecting tiles. Then there are two discs in total (one red and one blue) which means there are a total of two outcomes when selecting discs.

To select a card with S would be calculated as follows;

P(S) = Number of required outcomes/Number of all possible outcomes

P(S) = 1/4

P(S) = 0.25

To select a card with E would likewise be calculated as follows;

P(E) = Number of required outcomes/Number of possible outcomes

P(E) = 1/4

P(E) = 0.25

Therefore, the probability that a player selects a card with S or E is derived as follows;

P(S or E) = P(S) + P(E)

P(S or E) = 0.25 + 0.25

P(S or E) = 0.5

The probability that he selects a tile with 2 written on it is calculated as;

P(T2) = Number of required outcomes/Number of all possible outcomes

P(T2) = 1/2

P(T2) = 0.5

The probability that he will select a red disc is calculated as;

P(R) = Number of required outcomes/Number of possible outcomes

P(R) = 1/2

P(R) = 0.5

Therefore, the probability that the player selects a card with S or E, a tile with 2 and a red disc is calculated as;

P(S or E and T2 and R) = 0.5*0.5*0.5

P(S or E and T2 and R) = 0.125

Hence the probability that the player selects a card with S or E, a tile with 2 and a red disc is 0.125 (or 1/8).

5 0
3 years ago
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Answer:

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kirill [66]
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