Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Use the distributive property of multiplication.
25(-5x/2)=-62.5x, and 25(1/2)=12.5.
Add these together: -62.5x + 12.5 (answer)
Answer:
The solution is 
Step-by-step explanation:
The equation
can be rewritten as
and can be further simplified to
.
Now, taking the inverse sine of both sides we get:
The value of the right side on the interval 
is
,
which makes the equation (2)
solving for 
gives
which is our solution.
Absolute value is simply the distance from zero on a number line. -44 is 44 away from zero, so the absolute value of -44 is
44
