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VMariaS [17]
2 years ago
13

Which of the following statements is true

Mathematics
1 answer:
kolbaska11 [484]2 years ago
5 0

Answer:

D. This quadratic equation two complex solutions.

Step-by-step explanation:

5x^2 +6x +2= 0\\

Equating it with

ax^2 +bx +c= 0\\

a = 5, b = 6, c = 2

b^2 -4ac\\= 6^2 - 4\times 5\times 2\\= 36-40\\b^2 -4ac= - 4\\

\because b^2 -4ac is negative.

Therefore, this quadratic equation two complex solutions.

You might be interested in
Which statement accurately describes how to reflect point A(3,-1) over the y-axis?
Lyrx [107]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The rule of the reflection of a point over the y-axis is equal to

A(x,y) ----->A'(-x,y)

That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same

so

A(3,-1) ------> A'(-3,-1)

The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)

therefore

To reflect a point over the y-axis

Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis

6 0
2 years ago
The weight of Jane and Jessica was in the ratio of 8 : 9. Jane gained 2 kg while Jessica lost 4 kg. They then had the same weigh
postnew [5]

Answer:

  48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

__

<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

  x/y = 8/9

After the changes in weight, they were equal:

  x+2 = y-4

__

<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

  y = x +6 . . . . . . . . . . solve the second equation for y

  x/(x+6) = 8/9 . . . . . . substitute for y in the first equation

  9x = 8(x +6) . . . . . . . multiply by 9(x+6)

  x = 48 . . . . . . . . . . . simplify and subtract 8x

Jane weighed 48 kg at first.

_____

<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)

3 0
1 year ago
Can someone help with these? ik the answers i just don’t know how to show work
Nonamiya [84]

Step-by-step explanation:

use trigonometry ratios

8 0
2 years ago
$700 is invested at 4% per annum. How long will it take for the amount to reach $784?​
Blababa [14]

Answer:

3yrs

Step-by-step explanation:

Given parameters:

Capital = $700

Percentage interest  = 4% per annum

Unknown:

Time it will take for amount to be  = $784

Solution:

To find the simple interest on an amount;

        I = \frac{PRT}{100}

P is the principal

R is the rate

T is the time

I is the interest

    Insert the parameters:

        I  = \frac{700x 4 x T}{100}

        I = 28T

So;

   At the end of the duration:

       Principal + Interest  = Amount

          700+28T = 784

                   28T = 784 - 700

                   28T = 84

                       T = 3yrs

5 0
2 years ago
Question set 2: Many species of terrestrial tree frogs that hibernate at or near the ground surface can survive prolonged exposu
joja [24]

Answer:

0.86

Step-by-step explanation:

The z-score we need to make the comparison is given by

\bf z=\frac{-2.05-(-2)}{\sigma/\sqrt{n}}

where

\bf \sigma= the standard deviation established in the study

n = the sample size

\bf z=\frac{-2.05-(-2)}{0.3/\sqrt{42}}=-1.0801

and for the Normal distribution N(0,1) we want to find  

<em>P(X > -1.0801) </em>

By using a spreadsheet or the table attached, we find that

P(X > -1.0801) = 0.86

(See picture attached)

7 0
3 years ago
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