It is shifted to the right by a length of pi (this comes from the -pi part) and shifted down by a length of 1 (from the -1 part)
Answer:
B
Step-by-step explanation:
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the following Half-Angle Identities:
sin² A = (1 - cos 2A)/2
cos² A = (1 + cos 2A)/2
<u>Proof LHS → RHS:</u>
LHS: sin⁴ A
Expand: sin² A · sin² A
![\text{Half-Angle:}\qquad \qquad \bigg(\dfrac{1-\cos (2A)}{2}\bigg)\bigg(\dfrac{1-\cos (2A)}{2}\bigg)](https://tex.z-dn.net/?f=%5Ctext%7BHalf-Angle%3A%7D%5Cqquad%20%5Cqquad%20%5Cbigg%28%5Cdfrac%7B1-%5Ccos%20%282A%29%7D%7B2%7D%5Cbigg%29%5Cbigg%28%5Cdfrac%7B1-%5Ccos%20%282A%29%7D%7B2%7D%5Cbigg%29)
![\text{Distribute:}\qquad \qquad \dfrac{1-2\cos (2A)+\cos^2 (2A)}{4}](https://tex.z-dn.net/?f=%5Ctext%7BDistribute%3A%7D%5Cqquad%20%5Cqquad%20%5Cdfrac%7B1-2%5Ccos%20%282A%29%2B%5Ccos%5E2%20%282A%29%7D%7B4%7D)
![\text{Half-Angle:}\qquad \qquad \dfrac{1-2\cos (2A)+\frac{1+\cos (2\cdot 2A)}{2}}{4}](https://tex.z-dn.net/?f=%5Ctext%7BHalf-Angle%3A%7D%5Cqquad%20%5Cqquad%20%5Cdfrac%7B1-2%5Ccos%20%282A%29%2B%5Cfrac%7B1%2B%5Ccos%20%282%5Ccdot%202A%29%7D%7B2%7D%7D%7B4%7D)
![\text{Simplify:}\qquad \qquad \dfrac{\frac{2}{2}[1-2\cos (2A)]+\frac{1+\cos (4A)}{2}}{4}](https://tex.z-dn.net/?f=%5Ctext%7BSimplify%3A%7D%5Cqquad%20%5Cqquad%20%5Cdfrac%7B%5Cfrac%7B2%7D%7B2%7D%5B1-2%5Ccos%20%282A%29%5D%2B%5Cfrac%7B1%2B%5Ccos%20%284A%29%7D%7B2%7D%7D%7B4%7D)
![=\dfrac{2-4\cos (2A) + 1 + \cos (4A)}{8}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B2-4%5Ccos%20%282A%29%20%2B%201%20%2B%20%5Ccos%20%284A%29%7D%7B8%7D)
![=\dfrac{1}{8}\bigg(3-4\cos (2A)+\cos (4A)\bigg)](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B8%7D%5Cbigg%283-4%5Ccos%20%282A%29%2B%5Ccos%20%284A%29%5Cbigg%29)
LHS = RHS ![\checkmark](https://tex.z-dn.net/?f=%5Ccheckmark)
Answer:
15 - 10 = 5
Step-by-step explanation:
difference of p and 6 is two (8 - 6 = 2)
So 15 - 5(2) = 15 - 10 = 5