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aev [14]
3 years ago
9

A half-Dollar has a diameter of about 31 millimeters. About how many millimeters long would a row of 56 half-dollars be?

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
Multiply 31 mm by 56:

56(31 mm) = 1736 mm (answer)
disa [49]3 years ago
4 0

Answer:

A row of 56 half-dollars be 1736 mm long

Step-by-step explanation:

A half-Dollar has a diameter of about 31 millimeters.

Diameter of half dollar = 31 mm

About how many millimeters long would a row of 56 half-dollars.

So we are arranging 56 half dollars in 1 row

Total length = Number half dollars x Diameter of half dollar

Total length = 56 x 31 = 1736 mm

A row of 56 half-dollars be 1736 mm long

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Answer:

\huge\boxed{\text{D)} \  15x^4 + 2x^3 - 8x^2 - 22x - 15}

Step-by-step explanation:

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To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.

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Let's first start by multiplying the first term of the first polynomial, 3x^2, by all of the terms in the second polynomial. (5x^2+4x+5)

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Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.

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This simplifies our expression down to 15x^4 + 2x^3 - 8x^2 - 22x - 15.

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