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4 years ago

In the accompanying diagram, AEFB, AD II EC , DF || CB, mDAE = 34 and m DFE = 57. Find

Mathematics

1 answer:

scoray [572]4 years ago

8 0

Answer:

1. Solve small triangle

2. 180-90-57=33

3.solve medium triangle

4. E=33

5.C=90

6.180-90-33=57

7.B=57

8. solve big triangle

9.A=34

10.F=57

11.D=90

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Three-fifths of a number increased by ten

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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cupoosta [38]

Answer:

$\angle m + \angle t + \angle n = 180$

Step-by-step explanation:

Required

Show that:

$\angle m + \angle t + \angle n = 180^o$

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside $\angle m$ are alternate to $\angle t$ and $\angle n$

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Rewrite as:

$\angle m + \angle t + \angle n = 180$ -- proved

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